0=x^2-8x-2560

Solution for 0=x^2-8x-2560 equation:

0=x^2-8x-2560

We move all terms to the left:

0-(x^2-8x-2560)=0

We add all the numbers together, and all the variables

-(x^2-8x-2560)=0

We get rid of parentheses

-x^2+8x+2560=0

We add all the numbers together, and all the variables

-1x^2+8x+2560=0

a = -1; b = 8; c = +2560;
Δ = b2-4ac
Δ = 82-4·(-1)·2560
Δ = 10304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10304}=\sqrt{64*161}=\sqrt{64}*\sqrt{161}=8\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{161}}{2*-1}=\frac{-8-8\sqrt{161}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{161}}{2*-1}=\frac{-8+8\sqrt{161}}{-2}
$